At a given place on earth's surface the horizontal component of earths magnetic field is 2 × 10^-5 T and resultant magnetic field is 4 × 10^-5 T. The angle of dip at this place is?
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The value of earth's magnetic field can beA) 0.5GB) 5GC) 10GD) 50G
Which of the following is minimum at the equator?
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If the horizontal component of earth's magnetic field at a place where the angle of dip is 60^@ is 0*4xx10^-4T, calculate the vertical component and the resultant magnetic field at that place.
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The horizontal component of the earth's magnetic field is 3.6 xx 10^(-5) T where the dip is 60^@. Find the magnitude of the earth's magnetic field.
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![The value of horizontal component of the earth's magnetic field at a point is \\[0.5\\times {{10}^{-4}}\\text{tesla}\\] and the angle of dip is \\[\\text{45}{}^\\circ \\]. Find the value of vertical components.](https://www.vedantu.com/question-sets/932b2524-1834-4bc1-af87-9bb8910ffc48186918865695295683.png "The value of horizontal component of the earth's magnetic field at a point is \\[0.5\\times {{10}^{-4}}\\text{tesla}\\] and the angle of dip is \\[\\text{45}{}^\\circ \\]. Find the value of vertical components.")
The value of horizontal component of the earth's magnetic field at a point is \\[0.5\\times {{10}^{-4}}\\text{tesla}\\] and the angle of dip is \\[\\text{45}{}^\\circ \\]. Find the value of vertical components.
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On the surface of the earth, at a point on its magnetic equator, the earth's magnetic field induction B is measured to be 4×10^ 5. With this value of B the magnetic
